A particle is projected from a horizontal plane (x−z plane) such that its velocity vector at time t is given by →V=a^i+(b−ct)^j. Its range on the horizontal plane is given by
A
bac
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B
2bac
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C
3bac
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D
ac
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Solution
The correct option is B2bac Accroding to question vx=ux=a vy=uy−gt=b−ct
On comparing we get g=c and uy=b
We know that R=2uxuyg ∴R=2abc