Question

A particle is projected from a point $(1,1)$ aiming towards a point $(5,9)$. It fell on ground along x axis after $1sec$. If it falls on x-axis then the x-co-ordinate of that point is $(g=10m/s^2)$

• A. 1
• B. 2
• C. 3
• D. 4

Answer 1

Answer: (A), (D)

The correct options are
A 1
D 4

Slope=tan$\theta =\frac{9-1}{5-1}=2$

sin$\theta =\frac{2}{\sqrt{5}}$

cos$\theta =\frac{1}{\sqrt{5}}$

It reaches (x,0)

Distance travelled vertically is 1 and horizontally is x-1

Using $s=ut+\frac{1}{2}a{t}^2$

Along vertical path $1=vsin\theta \times 1-\frac{1}{2}g\times 1^2$

$v=3\sqrt{5}$

Along horizontal path $x-1=vcos\theta \times 1$

x=4