A particle is projected from ground with a speed of v 0-80 m - s at angle of 60- with horizontal- During first 3 seconds average velocity is V - acceleration is a- - displacement is - r- then a - v - r equals toA- 20 unitsB- 36 unitsC- 40 unitsD- Zero

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Standard XII

Physics

Problem Set

A particle is...

Question

A particle is projected from ground with a speed of $v_{0} = 80 m / s$ at angle of $60^{\circ}$ with horizontal. During first 3 seconds average velocity is $\to v$ & acceleration is $\to a$ & displacement is $- \to Δ r$ , then $(\to a \times \to v) . - \to Δ r$ equals to

20 u n i t s

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36 u n i t s

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40 \sqrt{3} u n i t s

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Z e r o

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Solution

The correct option is D $Z e r o$
All vectors are coplanar, hence $(\to a \times \to v) . - \to Δ r = 0$

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A particle is projected from ground with a speed of v0=80 m/s at angle of 60∘ with horizontal. During first 3 seconds average velocity is →v & acceleration is →a & displacement is −→Δr, then (→a×→v).−→Δr equals to

The correct option is D ZeroAll vectors are coplanar, hence (→a×→v).−→Δr=0

A particle is projected from ground with a speed of $v_{0} = 80 m / s$ at angle of $60^{\circ}$ with horizontal. During first 3 seconds average velocity is $\to v$ & acceleration is $\to a$ & displacement is $- \to Δ r$ , then $(\to a \times \to v) . - \to Δ r$ equals to

The correct option is D $Z e r o$
All vectors are coplanar, hence $(\to a \times \to v) . - \to Δ r = 0$