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Question

# A particle is projected from ground with initial speed u at angle θ with horizontal. If air friction is absent, then the average velocity of complete motion will be:

A
ucosθ
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B
usinθ
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C
2ucosθ
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D
2usinθ
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Solution

## The correct option is A ucosθTo know the average time traveled from being one point of height to other which is same from the ground determines the parabolic shapes of projectile.Hence given as speed u at angle \theta and time as t1 and t1 . Horizontal component of the velocity be u cos \theta and the total displacement in travelling from t1 to t2 be,ucosθ×(t1−t2) => Total time taken be(t1−t2)Therefore the average velocity be,Va=TotaldisplacementTotaltime=Va=ucosθ×(t1−t2)(t1−t2)=ucosθHence,option (A) is correct answer.

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