A particle is projected from ground with speed 80 m/s at an angle 30^0 with horizontal from ground the magnitude of average velocity of particle in time interval t=2s to t=6s is

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Q. A particle is projected from ground with speed 80 m/s at an angle

30^{0}

with horizontal from ground. The magnitude of average velocity of particle in time interval t = 2 s to t = 6 s is [Take g = 10

m / s^{2}

Q. A particle is projected from ground with speed

80 m / s

at an angle

30^{o}

with horizontal from ground.The magnitude of average velocity of the particle in time interval

t = 2 s

t = 6 s

is [Take

g = 10 m / s^{2}

]

A particle from ground with speed $80 m / s$ at an angle $30^{\circ}$ with horizontal from ground. The magnitude of average velocity of particle in time interval $t = 2 s$ to $t = 6 s$ is [ Take g = $10 m / s^{2}$ ]

Q. A particle is projected from the ground with an initial velocity of

20 m / s

at an angle of

30^{\circ}

with horizontal. The magnitude of change in velocity in a time interval from

t = 0

t = 0.5 s

(g = 10 m / s^{2})

Q. A particle is projected from the ground with an initial velocity of

20

m/s at an angle of

30^{o}

with horizontal. The magnitude of change in velocity in a time interval from

t = 0

t = 0.5

s is

(g = 10 m / s^{2})

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