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Question

A particle is projected from the bottom of an inclined plane of angle 30 with a velocity of 30 m/s at an angle of 60 with the horizontal. Find the time of flight.
(Take g=10 m/s2)

A
3 s
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B
13 s
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C
23 s
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D
2 s
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Solution

The correct option is C 23 s
We know that time of flight of a projectile on an inclined plane is given by
T=2usin(αθ)gcosθ
Here α=60 and θ=30
T=2×30×sin(6030)gcos30
T=23 s

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