A particle is projected from the bottom of an inclined plane of inclination $30^{0}$ with the velocity of $40 m / s$ . Find the speed of the particle when its velocity vector is parallel to the plane. Take $g = 10 m / s^{2}$ .

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Solution

Velocity vector will be parallel to plane in projectile motion at highest point.
$v_{y} = 0$
$v_{x} = v cos θ$
$= 40 cos 30^{\circ}$
$= \frac{40 \times \sqrt{3}}{2}$
$= 34.6 m / s$

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A particle is projected from the bottom of an inclined plane of inclination 300 with the velocity of 40m/s. Find the speed of the particle when its velocity vector is parallel to the plane. Take g=10m/s2.

Velocity vector will be parallel to plane in projectile motion at highest point.vy=0vx=vcosθ=40cos30∘=40×√32=34.6m/s

A particle is projected from the bottom of an inclined plane of inclination $30^{0}$ with the velocity of $40 m / s$ . Find the speed of the particle when its velocity vector is parallel to the plane. Take $g = 10 m / s^{2}$ .

Velocity vector will be parallel to plane in projectile motion at highest point.
$v_{y} = 0$
$v_{x} = v cos θ$
$= 40 cos 30^{\circ}$
$= \frac{40 \times \sqrt{3}}{2}$
$= 34.6 m / s$