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Question

A particle is projected from the ground at some angle to the horizontal. (Assuming point of projection to be the origin and the horizontal and vertical directions to be the x & y-axis) the particle passes through the points (3,4) and (4,3) during its motion then the range of the particle would be:

A
36m
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B
377m
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C
4m
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D
16m
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Solution

The correct option is A 377m
Be equation of trajectory (y=xtan[y=xtanα[1xR]]
4=3tanα[13R] ...(i)
3=4tanα[14R] ...(ii)
dividing (i) & (ii)
43=34[13R]14R16[14R]=9[13R]
7=64R27RR=377

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