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Question

A particle is projected making an angle of 45 with horizontal, with kinetic energy K. The kinetic energy at highest point will be

A
K2
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B
K2
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C
2K
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D
K
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Solution

The correct option is B K2

Kinetic energy at initial point: K1=12mv2 ...(1)
Kinetic energy at highest point: K2=12mv2Velocity at highest point,v=v2 K2=12m[v2]2 =14mv2 ...(2)

On comparing eq.(1) and eq. (2),
K2=12K1
or K2=12K

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