Question

A particle is projected such that the horizontal range and vertical height are the same. What is the angle of projection?

Answer 1

Given, H = R
$\Rightarrow \frac{u^{2}si{n}^2\theta }{2g}=\frac{u^{2}sin2\theta }{g}\Rightarrow \frac{sin\theta }{2}=2cos\theta \Rightarrow tan\theta =4$
$\Rightarrow \theta =ta{n}^{-1}\left(4\right)$