Question

A particle is projected under gravity at an angle of projection ${45}^{\circ }$. If for ground projectile motion its range is 36m. Find maximum Height attained by particle in S I units is

• A. 9
• B. 8
• C. 7
• D. 6

Answer 1

The correct option is A

9

$\frac{H}{R}$ = $\frac{tan\theta }{4}$

$\theta$ = ${45}^{\circ }$ & R = 36 m

H = 9 m