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Question

A particle is projected up with a velocity of 20 m s−1 from the tower of height 25 m. Its velocity on reaching the ground is _____ m s−1

A
30
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B
60
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C
120
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D
20
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Solution

The correct option is A 30
Initial horizontal component of velocity ux=20 m/s
Since there is no acceleration in horizontal direction, so horizontal component of velocity remains the same.
Final horizontal component of velocity of particle when it reaches the ground vx=ux=20 m/s
Vertical direction :
Final vertical component of velocity of particle when it reaches the ground vy=2gh
where h=25 m and g=10 m/s2
vy=2×10×25=500 m/s
Net velocity of particle v=(vx)2+(vy)2=202+500=900=30 m/s

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