Question

A particle is projected up with a velocity of $v_0$ = 10 m/s at an angle pf ${\theta }_0={60}^0$ with horizontal onto an inclined plane. The angle of inclination of the plane is ${30}^0$. The time of flight of the particle till it strikes the plane is (take g = 10 $m/s^2$)

Answer 1

Given : $v_o=10m/s$ ${\theta }_o={60}^o$

Angle of inclination $\alpha ={30}^o$

Time of flight $T=\frac{2v_o\sin {\theta }_o}{g\cos \alpha }$

$⟹T=\frac{2\times 10\times \sin {60}^o}{10\times \cos {30}^o}=2s$