A particle is projected vertically upward and it reaches a point 25m hieght at instant. After 4 seconds from this instant particle reaches again that point in downward journey.What will be the initial velocity.(g=10m/s²).?

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Solution

2sec to reach the highest point where velocity will be zero(0) from the point 25 m above the ground .
V=u-gt
V=20m/s
Again, v^2-u^2=-2gs
V=20,u=?,s=25
u=30m/s

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A particle is projected vertically upward and it reaches a point 25m hieght at instant. After 4 seconds from this instant particle reaches again that point in downward journey.What will be the initial velocity.(g=10m/s​​​​​​2).?

2sec to reach the highest point where velocity will be zero(0) from the point 25 m above the ground . V=u-gt V=20m/s Again, v^2-u^2=-2gs V=20,u=?,s=25 u=30m/s

A particle is projected vertically upward and it reaches a point 25m hieght at instant. After 4 seconds from this instant particle reaches again that point in downward journey.What will be the initial velocity.(g=10m/s²).?

2sec to reach the highest point where velocity will be zero(0) from the point 25 m above the ground .
V=u-gt
V=20m/s
Again, v^2-u^2=-2gs
V=20,u=?,s=25
u=30m/s