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Question

A particle is projected vertically upwards from a point A on the ground. it makes time t1 to reach a point B, but it still continues to move up . If it takes further time t2 to reach the ground from point B. Then height of point B from the ground is:

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Solution

Let the height of point B be 'h' and initial velocity of particle be 'u'.
Total time of light =t1+t2
So, time to reach at maximum height =t1+t22
Applying I equation of motion
0=u+(g)[t1+t22]
u=g(t1+t2)2
Applying II equation of motion
h=ut112gt21
=g(t1+t2)t12gt212
h=gt1t22.

1381449_1210143_ans_4eedc89e5c2b4b7ea7e92d712b179b77.PNG

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