A particle is projected vertically upwards with a speed of $16 m / s$ . After a time when it again passes through the point of projection, its speed is found to be $8 m / s$ . It is known that the work done by air resistance, is same during upward and downward motion. Then the maximum height attained by the particle is ? (take ( $g = 10 m s^{- 2}$ )

8 m

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4.8 m

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17.6 m

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12.8 m

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Solution

The correct option is B $4.8 m$

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