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Question

A particle is projected vertically upwards with speed 20 m/s from top of a tower of height 20 m as shown in figure. Given B is top most point of trajectory and C is at same height as A.
List-I gives certain statements regarding particle
List - II gives corresponding results in SI units.
Match the statements in List-I with corresponding results in List-II.

List-IList-II(I)ratio of maximum height from ground (BD)(P)12to the initial height from ground (AD) is(II)ratio of distance travelled in 1st second to(Q)1the distance travelled in 2nd second is(III)ratio of initial speed at A to the final(R)2just before reaching to ground (D) is(IV) ratio of time taken from A to C and time (S)3taken from A to B is

A
IR; IIS; IIIR; IVP
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B
IS; IIR; IIIP; IVR
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C
IR; IIS; IIIP; IVR
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D
IP; IIS; IIIQ; IVR
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Solution

The correct option is C IR; IIS; IIIP; IVR
(I) AB= maximum height =v22g=20×202×10=20 m
BDAD=20+2020=2

(II) s(1st)s(2nd)=20×112×10×1220[15]=155=3

(III) vAvD=20202+2×10×20=20202=12

(IV) tACtAB=2tABtAB=2

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