A particle is projected vertically upwards with velocity $40 m / s$ . Take $g = 10 m / s^{2} .$ Find the distance traveled by the particle in $2 s$ .

30 m

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40 m

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60 m

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80 m

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Solution

The correct option is B $60 m$
Given :
Initial velocity, $u = 40 m / s$

Acceleration of the particle is, $a = - 10 m / s^{2}$ for a free fall.

Using second equation of motion,
$s = u t + \frac{1}{2} a t^{2}$
$s = 40 \times 2 + \frac{1}{2} \times (- 10) \times 2^{2}$
$s = 60 m$

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