Question

A particle is projected vertically upwards with velocity $80$ m/s. Then the (Take $g=10$ $m/s^2$):

• A. Displacement and distance travelled by the particle in $2$ sec in $160$m
• B. Displacement and distance travelled by the particle in $4$ sec in $240$m
• C. Displacement and distance travelled by the particle in $6$ sec in $300$m and $100$m
• D. Displacement and distance travelled by the particle in $8$ sec is $320$m and $10$m

Answer 1

The correct option is A Displacement and distance travelled by the particle in $2$ sec in $160$m

Time of flight T$=\frac{v\sin \theta }{g}$ where $t=2$ sec and $v=80$ m/s$

$\theta ={sin}^{-1}\left(\frac{1}{4}\right)$

Displacement =range$=\frac{v^2\sin \theta }{g}=\frac{{80}^{2}sin\left(si{n}^{-1}\frac{1}{4}\right)}{10}=160$