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Standard XII

Physics

The 'e' Equation

A particle is...

Question

A particle is projected with a speed u at an angle $θ$ with horizontal from point A. It strikes elastically with a vertical wall at height h/2. It rebounds and reaches maximum height h and falls back on the ground at point B as shown in figure. Distances from A to wall and from wall to B are $x_{1}$ and $x_{2}$ , respectively, and time to cover $x_{1}$ and $x_{2}$ are $t_{1}$ and $t_{2}$ , respectively. Match the values in column I with the expressions in column II.

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Solution

$A - 1, 2$
$B - 2$
$C - 4$
$D - 3$

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Similar questions

Q. A particle is projected with a speed

u

at an angle

θ

with horizontal from point

A

. It strikes elastically with a vertical wall at height

h / 2

. It rebounds and reaches maximum height

h

and falls back on the ground at point

B

as shown in Figure. Distances from

A

to wall and from wall to

B

are

x_{1}

and

x_{2}

, and time to cover is

t_{1}

and

t_{2}

respectively. Match the values in column I with the expressions in column II.

\begin{matrix} Column I & Column II i. \sqrt{2} & a. \frac{x_{2} - x_{1}}{x_{2} + x_{1}} or \frac{x_{2} + x_{1}}{x_{2} - x_{1}} ii. \frac{1}{\sqrt{2}} & b. \frac{t_{2} - t_{1}}{t_{2} + t_{1}} or \frac{t_{2} + t_{1}}{t_{2} - t_{1}} iii. 1 & c. \frac{u sin θ}{g (t_{2} + t_{1})} iv. \frac{1}{2} & d. \frac{u cos θ (t_{1} + t_{2})}{x_{1} + x_{2}} \end{matrix}

Q. A particle is projected with speed

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with horizontal from ground. If it is at same height from ground at time

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t_{2}

Q. A particle is projected from the ground at

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so that on its way it just clears two vertical walls of equal height on the ground. The particle was projected with initial velocity

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and at angle

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with the horizontal. If the particle passes just grazing top of the wall at time

t = t_{1}

and

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and

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A particle is projected from point A on the ground at an angle $θ$ with horizontal. Another particle is projected from point B simultaneously from height 4H above point A with same velocity. A and B are in the same vertical plane, where H is the maximum height attained by the particle A. Both the particles collide at the same time on the ground. Find the angle at which particle B is projected with horizontal:

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A−1,2B−2C−4D−3

$A - 1, 2$
$B - 2$
$C - 4$
$D - 3$