Question

A particle is projected with a velocity of 30 m/s, at an angle of ${\theta }_0=ta{n}^{-1}\left(3/4\right)$. After 1 second, the particle is moving at an angle $\theta$ to the horizontal, where tan $\theta$ is given by $(g=10m{s}^{-2})$

• A. 1
• B. 2
• C. 1/2
• D. 1/3

Answer 1

The correct option is D 1/3

$v_x=ucos\theta =24m{s}^{-1}{v}_y=usin\theta -g=8m{s}^{-1}\therefore tan\theta =\frac{v_y}{v_x}=\frac{1}{3}$