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Question

A particle is projected with a velocity u making an angle θ with the horizontal. What is the radius of curvature of the parabola where the particle makes an angle θ /2 with the horizontal?

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Solution

vin=ucosθ^i+usinθ^jandv(t)=ucosθ^i+(usinθgt)^jattimettheangleoftheprojectileisθ/2usinθgtucosθ=tanθ/2usinθgt=ucosθtanθ/2v(t)=ucosθ^i+(ucosθtanθ/2)^jv=(ucosθ)2+(ucosθtanθ/2)2v=ucosθsecθ/2R=v2gcosθ/2=u2cos2θsec2θ/2gcosθ/2=u2cos2θgcos3θ/2

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