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Standard XII

Physics

Matter Waves

A particle is...

Question

A particle is projected with an initial velocity of $200 m / s$ in a direction making an angle of $30^{o}$ with the vertical. The horizontal distance covered by the particle in $3 s$ is

300 m

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150 m

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175 m

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125 m

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Solution

The correct option is B $300 m$
$v_{x} =$ Horizontal velocity $= v c o s 60^{o} = 200 c o s 60^{o}$
In horizontal direction, there is no acceleration or deceleration,
Hence, $x = v_{x} t = 200 c o s 60^{o} \times 3$ $= 600 c o s 60^{o} = 300 m$

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A particle is projected with an initial velocity of 200 m/s in a direction making an angle of 30o with the vertical. The horizontal distance covered by the particle in 3 s is

The correct option is B 300 mvx= Horizontal velocity =vcos60o=200cos60oIn horizontal direction, there is no acceleration or deceleration,Hence, x=vxt=200cos60o×3=600cos60o=300m

A particle is projected with an initial velocity of $200 m / s$ in a direction making an angle of $30^{o}$ with the vertical. The horizontal distance covered by the particle in $3 s$ is

The correct option is B $300 m$
$v_{x} =$ Horizontal velocity $= v c o s 60^{o} = 200 c o s 60^{o}$
In horizontal direction, there is no acceleration or deceleration,
Hence, $x = v_{x} t = 200 c o s 60^{o} \times 3$ $= 600 c o s 60^{o} = 300 m$