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Relative Velocity

A particle is...

Question

A particle is projected with initial speed 10 m/s at an angle of $53^{\circ}$ with horizontal. Then the time after which its speed becomes half of the initial speed.

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Solution

$V_{L} = 10 c o s 53 = 10 \times \frac{3}{5} = 6 m / s$
The speed of body will be $\sqrt{V_{x}^{2} + V_{y}^{2}}$
$= \sqrt{36 + V_{y}^{2}} \geq 6$
So, the correct ans. is never

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