Question

# A particle is projected with initial speed 10 m/s at an angle of 53∘ with horizontal. Then the time after which its speed becomes half of the initial speed.

Solution

## VL=10 cos 53=10×35=6 m/s The speed of body will be √V2x+V2y =√36+V2y≥6 So, the correct ans. is never

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