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Question

A particle is projected with velocity 2gh and at an angle 60 the horizontal so that it just clear two walls of equal height h which are at a distance 2h from each other. The time taken by the particle to travels between these two walls is

A
22hg
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B
h2g
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C
2hg
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D
hg
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Solution

The correct option is A 2hg
Given - u=2gh,θ=60o, horizontal distance d=2h
As the particle is projected with an initial velocity , at an angle with horizontal ,therefore it is a projectile motion . We know that , the horizontal velocity remains constant in a projectile motion .
Hence , horizontal velocity of particle is
ux=ucosθ
or ux=2gh×cos60
or ux=2gh×1/2=gh
Therefore , time taken by particle to cover the horizontal distance of 2h will be ,
t=2h/ux=2h/gh=2h/g

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