Question

A particle is projected with velocity ${30}^{\circ }$ above on an inclined plane, inclination of which from horizontal is ${37}^{\circ }$. Choose appropriate path (air resistance is negligible)

• A.
• B.
• C.
• D.

Answer 1

The correct option is B


As motion along incline plane will be a retarding motion so after time $T$ horizontal component of velocity decreases but $v_y$ remains same so angle of strike is greater than angle of projection.
$\tan \theta =\frac{v_y}{v_x}$

Final Answer: $\left(d\right)$