Question

A particle is projected with velocity 50 m/s such that its initial velocity makes an angle ${37}^o$ with east direction and the vertical plane. The particle has constant acceleration 10 $m/s^2$ towards north due to wind and $10m/s^2$ downwards due to gravity.

The time of flight of particle is.

• A. 10 sec.
• B. 8 sec.
• C. 6 sec.
• D. None of these

Answer 1

The correct option is C 6 sec.

Only gravity will have effect to bring the particle down and North acceleration is just going to distort the direction of Range towards North. Therefore, we can apply the standard formula

$T=\frac{2usin\theta }{g}=\frac{2\times 50\times sin{37}^o}{10}=6s$