Question

A particle is projected with velocity 'u' at an angle $\theta$ with an inclined plane of inclination $\theta <45$ with the horizontal.The time taken when velocity of projectile becomes parallel to the plane

• A. $\frac{u\sin \theta }{g}$
• B. $\frac{u\cot \theta }{g}$
• C. $\frac{2u\tan \theta }{g}$
• D. $\frac{u\tan \theta }{g}$

Answer 1

The correct option is A $\frac{u\sin \theta }{g}$

The velocity of projectile is parallel to the plane when projectile is at maximum height. And we know that time taken to reach for maximum height is U/g * sin theta.