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Standard XII

Physics

Centripetal Acceleration

A particle is...

Question

A particle is revolving in a circular path of radius 2 m with constant angular speed 4 rad/s. The angular acceleration of particle is

Zero

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{8 π}^{2} r a d / s^{2}

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{16 π}^{2} r a d / s^{2}

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{128 π}^{2} r a d / s^{2}

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Solution

The correct option is C Zero
Given,

The radius of the circular path $r = 2 m$

Angular velocity $ω = 4 r a d / s$

Angular acceleration α is rate of change of angular velocity

$α = \frac{ω}{t}$

Here in the question, the angular velocity is given as constant

Therefore, the angular velocity is not changing with time

Thus, angular acceleration $α = 0$

Suggest Corrections

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