A particle is shifted from point (0,0,1m) to (1m,1m,2m), under the simultaneous action of several forces. Two of the forces are −→F1=(2^i+3^j−^k)N and −→F2=(^i−2^j+2^k)N. Find the work done by these two forces
A
7J
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
5J
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
10J
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
12J
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is B5J As particle is shifted from point (0,0,1m) to (1m,1m,2m) Displacement vector Δ→r=(^i+^j+^k) net force acting is −→F1+−→F2=(2^i+3^j−^k)N+(^i−2^j+2^k)N=(3^i+^j+^k) Work done by a constant force equals to the dot product of the force and displacement vectors. W=→F.Δ→r⇒W=(−→F1+−→F2).Δ→r Substituting the given values, we have W=(3^i+^j+^k).(^i+^j+^k)=3+1+1=5J