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Question

A particle is subjected to two mutually perpendicular simple harmonic motions such that its x and y coordinates are given by x=2 sin ωt: y=2 sin ωt+π4
The path of the particle will be
(a) a straight line (b) a circle (c) an ellipse (d) a parabola

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Solution

Dear Student ,
As the phase difference is constant that is ϕ=π4 . So the resultant path of the particle will be an ellipse .
Here x=sinωt and y =cosωt+π4So squaring and adding both sides we can write that ,x2+y24=1So the path will be ellipse .
Regards

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