1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

# A particle is subjected to two simple harmonic motions along x and y directions according to x=3 sin100πt andy=4 sin100πt. Choose the correct statement(s).

A
Motion of particle will be on ellipse travelling in clockwise direction.
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
Motion of particle will be on a straight line with slope 43.
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
Motion will be simple harmonic motion with amplitude 5.
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
Phase difference between two motions is π2.
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

## The correct options are B Motion of particle will be on a straight line with slope 43. C Motion will be simple harmonic motion with amplitude 5.x=3sin100πt y=4sin100πt Equation of path is yx=43 i.e., y=43x which is equation of a straight line having slope 43. Equation of resulting motion is →r=x^i+y^j=(3^i+4^j)sin100πt Amplitude=√32+42=5 Phase difference between x and y motions is clearly zero.

Suggest Corrections
2
Join BYJU'S Learning Program
Related Videos
Aftermath of SHM
PHYSICS
Watch in App
Explore more
Join BYJU'S Learning Program