Question

A particle is subjected to two simple harmonic motions given by:
$y_1=10\sin \omega t$ and $y_2=5\sin (\omega t+\pi )$ The maximum speed of the particle is:

• A. $\sqrt{{10}^2+5^2\omega }$
• B. $\sqrt{{10}^2-5^2\omega }$
• C. $5\omega$
• D. $15\omega$

Answer 1

The correct option is C $5\omega$

$y=y_1+y_2$

$\Rightarrow y=10\sin wt+5\left(\sin \omega t+\pi \right)$

$\Rightarrow y=5\sin \omega t$

$\therefore V_{max}=5\omega$

hence,

option $\left(C\right)$ is correct answer.