Question

A particle is taken from A to point B under the influence of a force field. Now it is taken from B to A and it is observed that the work done in taking the particle from A to B is not equal to the work done in taking it from B to A. If $W_{nc}$ and $W_C$ are the work done by non-conservation and conservative force field respectively and $\Delta U$ and $\Delta K$, be the change in P.E and K.E then

• A. $W_{nc}-\Delta U=\Delta K$
• B. $W_C=-\Delta U$
• C. $W_{nc}+W_C=\Delta K$
• D. $W_{nc}=-\Delta U=-\Delta K$

Answer 1

Answer: (A), (B), (C)

The correct options are
A $W_{nc}-\Delta U=\Delta K$
B $W_C=-\Delta U$
C $W_{nc}+W_C=\Delta K$