Question

A particle is thrown upward with a speed u at an angle $\theta$ with the horizontal. When the particle makes an angle $\beta$ with the horizontal, its speed changes to v, then

• A. $v$ = $\frac{u\cos \theta }{\cos \beta }$
• B. $v=u\cos \theta \cos \beta$
• C. $v=u\cos \theta$
• D. $v=u\sec \theta \cos \beta$

Answer 1

The correct option is A $v$ = $\frac{u\cos \theta }{\cos \beta }$

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