CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

A particle is thrown vertically upwards. If its velocity at half of the maximum height is 10ms, then maximum height attained by it is (Take g =10 ms2)
  1. 20 m
  2. 5 m
  3. 15 m
  4. 10 m


Solution

The correct option is D 10 m
Let particle be thrown with velocity u and its maximum height is H, then H=u22g.

When particle is at height H2, then its speed is 10 ms
So, from equation,
v2=u22gh(10)2=u22g(H2)=u22g(u24g)
u2=200  m2/s2

Maximum height, H=u22g=2002×10=10 m 

flag
 Suggest corrections
thumbs-up
 
0 Upvotes


Similar questions
QuestionImage
QuestionImage
View More...


People also searched for
QuestionImage
QuestionImage
View More...



footer-image