Question

A particle is thrown vertically upwards. It's velocity at half of the height is $10\text{m/s}$, then the maximum height attained by it will be:

• A. $10\text{m}$
• B. $20\text{m}$
• C. $15\text{m}$
• D. $25\text{m}$

Answer 1

The correct option is A $10\text{m}$

Let maximum height be $H$
From the formula, $v^2=u^2-2gs$
$(10{)}^2=u^2-\frac{2gH}{2}=u^2-gH.....(i)$
For attaining maximum height, $v=0$
$0=u^2-2gH\Rightarrow u^2=2gH$
Putting the value of $u^2$ in equation $\left(i\right)$,
$100=2gH-gH=gH$
$H=\frac{100}{g}=\frac{100}{10}=10\text{m}$