A particle is thrown vertically upwards. It's velocity at half of the height is 10 m/s, then the maximum height attained by it will be:
A
10 m
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B
20 m
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C
15 m
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D
25 m
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Solution
The correct option is A10 m Let maximum height be H
From the formula, v2=u2−2gs (10)2=u2−2gH2=u2−gH.....(i)
For attaining maximum height, v=0 0=u2−2gH⇒u2=2gH
Putting the value of u2 in equation (i), 100=2gH−gH=gH H=100g=10010=10 m