A particle is thrown vertically upwards reaches the highest point in 4 seconds . Calculate the Initial speed of throw and maximuum height reached.

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Solution

Time taken(t)= 4 seconds
at highest point velocity is 0
so final velocity(v) = 0
acceleration due to gravity(g)= -9.8
negative because force is in opposite direction
we need to find initial velocity(u)
we know v=u+at
on substituting values
0=u+9.84
so u = 9.85 = 39.2 m/s

distance(s)= ut+1/2at^{2}
so,
s=439.2 - 1/29.844
s=156.8 - 78.4
S = 78.4 m

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