A particle is thrown vertically with a velocity of $50 m / s$ . What will be its velocity at the highest point of the journey? How high would the particle rise? What time would it take to reach the highest point ? ( $g = 10 m / s^{2}$ )

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Solution

$u = 50 m / s$
$g = - 10 m / s^{2}$
The velocity at the highest point will be zero
Thus, $v = 0$
Height can be calculated as,
$v^{2} - u^{2} = 2 g s$
$0 - 2500 = - 20 s$
$s = 125 m$
Time can be calculated as,
$v = u + g t$
$0 = 50 + (- 10) t$
$t = 5 s e c$

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A particle is thrown vertically with a velocity of 50m/s. What will be its velocity at the highest point of the journey? How high would the particle rise? What time would it take to reach the highest point ? (g=10m/s2)

u=50m/sg=−10m/s2The velocity at the highest point will be zeroThus, v=0Height can be calculated as,v2−u2=2gs0−2500=−20ss=125mTime can be calculated as,v=u+gt0=50+(−10)tt=5sec

A particle is thrown vertically with a velocity of $50 m / s$ . What will be its velocity at the highest point of the journey? How high would the particle rise? What time would it take to reach the highest point ? ( $g = 10 m / s^{2}$ )

$u = 50 m / s$
$g = - 10 m / s^{2}$
The velocity at the highest point will be zero
Thus, $v = 0$
Height can be calculated as,
$v^{2} - u^{2} = 2 g s$
$0 - 2500 = - 20 s$
$s = 125 m$
Time can be calculated as,
$v = u + g t$
$0 = 50 + (- 10) t$
$t = 5 s e c$