Question

A particle (mass m) is projected with an velocity v at an angle $\theta$ to the horizontal. What is the work done by the force of gravity from the instant of throwing to the instant it reaches the highest point?

• A. $m{v}^{2}sin\theta$
• B. zero
• C. $-m{v}^{2}sin\theta$
• D. $\frac{-m{v}^{2}si{n}^2\theta }{2}$

Answer 1

The correct option is D $\frac{-m{v}^{2}si{n}^2\theta }{2}$

Work done by the gravitational force$=\overrightarrow{F}.\overrightarrow{p}=mg\times H_{max}\cos {180}^{\circ }=\frac{-m{v}^2{\sin }^2\theta }{2}$