Question

A particle moved 10 m towards the east and then moved 10 m towards the north. The magnitude of the displacement and the total distance covered are_________ and _________, respectively.

• A. 10 $\sqrt{2}$ m, 20 m
• B. 20 m, 20 m
• C. 20 m, 10 $\sqrt{2}$ m
• D. 10 m, 20 m

Answer 1

The correct option is A

10 $\sqrt{2}$ m, 20 m

Step 1: Given data,

Particle moved to east= 10 m

Particle moved to north = 10 m.

Step 2: Displacement is the shortest distance between the initial point and the final point.

So particle distance east is 10 m and north is 10 m.

So displacement is the hypotenuse of the right-angled triangle formed = $\sqrt{{\left(10\right)}^2+{\left(10\right)}^2}$= $10\sqrt[]{2}$.

Distance covered= 10 +10 = 20 m.

Hence the correct option is (A)$10$ $\sqrt{2}$ $m,20m.$