A particle moves 3 m north, then 4 m east, and finally 6 m south. What is its displacement?

3 m

No worries! We‘ve got your back. Try BYJU‘S free classes today!

4 m

No worries! We‘ve got your back. Try BYJU‘S free classes today!

5 m

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

12 m

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C 5 m
Displacement = AE
AE = $\sqrt{(} A D^{2}$ + $D E^{2})$
Also, BC = AD
⇒ AE = $\sqrt{(} 4^{2}$ + $3^{2})$ = 5 m
Therefore,
Displacement = 5 m

Suggest Corrections

Similar questions

A particle moves 3 m north, then 4 m east and finally 6 m south. What is the distance travelled and the displacement of the particle?

Q. A particle moves

3 m

north, then

4 m

east, and then

12 m

vertically upwards, its displacement is:

Q. A person moves

20 m

towards north then

30 m

towards east and finally

30 \sqrt{2} m

south-west. His displacement is:-

A particle moves $3 m$ north, then $4 m$ east and finally $6 m$ south. Which of the following is correct about the distance travelled and the displacement?

A particle moves through 3 m due east, 4 m due north and finally 5 m vertically upward. if x,y and z axis are taken along east,north and upward direction respectively.

i) Represent the displacement vector its rectangular components.

ii) Find the magnitude of the resultant displacement.

Join BYJU'S Learning Program

A particle moves 3 m north, then 4 m east, and finally 6 m south. What is its displacement?

The correct option is C 5 mDisplacement = AE AE = √(AD2 + DE2) Also, BC = AD ⇒ AE = √(42 + 32) = 5 m Therefore, Displacement = 5 m

The correct option is C 5 m
Displacement = AE
AE = $\sqrt{(} A D^{2}$ + $D E^{2})$
Also, BC = AD
⇒ AE = $\sqrt{(} 4^{2}$ + $3^{2})$ = 5 m
Therefore,
Displacement = 5 m