A particle moves 3m north, then 4m east and finally 6m south. Which of the following is correct about the distance travelled and the displacement?
A particle moves 3m north, then 4m east and finally 6m south. Which of the following is correct about the distance travelled and the displacement?
Step 1: Given
Let the particle start traveling from point A and end at point B.
Particle movement in north = 3m
Particle movement in east = 4m
Particle movement in south = 6m
Step 2: Formula used
Distance is the length of the actual path taken by it.
Displacement is the shortest distance between the initial and final positions.
Hypotenuse² = Base² + perpendicular² (Pythagoras theorem)
Step 3: Finding the distance
In this case, distance =3m+4m+6m=13m
Step 4: Finding the displacement
In this case, displacement = AB
=√(BC2+AC2)
=√(32+42) m=5 m
Hence, the distance covered by the particle is 13 m and the displacement is 5 m.
Step 1: Given
Let the particle start traveling from point A and end at point B.
Particle movement in north = 3m
Particle movement in east = 4m
Particle movement in south = 6m
Step 2: Formula used
Distance is the length of the actual path taken by it.
Displacement is the shortest distance between the initial and final positions.
Hypotenuse² = Base² + perpendicular² (Pythagoras theorem)
Step 3: Finding the distance
In this case, distance =3m+4m+6m=13m
Step 4: Finding the displacement
In this case, displacement = AB
=√(BC2+AC2)
=√(32+42) m=5 m
Hence, the distance covered by the particle is 13 m and the displacement is 5 m.
