A particle moves 3m north, then 4m east and finally 6m south. Which of the following is correct about the distance travelled and the displacement?
5m, 13m
3m, 5m
Let the particle start from A and finally reach B as shown. Distance is the length of the actual path taken by it.
In this case, distance =3m+4m+6m=13m
Displacement is the shortest distance between the initial and final position.
In this case, displacement = AB
=√(BC2+AC2)
=√(32+42) m=5 m