wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A particle moves 3m north, then 4m east and finally 6m south. Which of the following is correct about the distance travelled and the displacement?


A

5m, 13m

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B

12m, 6m

No worries! We‘ve got your back. Try BYJU‘S free classes today!
C

13m, 5m

No worries! We‘ve got your back. Try BYJU‘S free classes today!
D

3m, 5m

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct options are
A

5m, 13m


D

3m, 5m



Let the particle start from A and finally reach B as shown. Distance is the length of the actual path taken by it.
In this case, distance =3m+4m+6m=13m

Displacement is the shortest distance between the initial and final position.
In this case, displacement = AB
=(BC2+AC2)
=(32+42) m=5 m


flag
Suggest Corrections
thumbs-up
9
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Distance and Displacement
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon