A particle moves according to the equation x=2t2−5t+6. The average velocity in the first 3s and velocity at t=3s are repectively.
A
1ms−1,7ms−1
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
4ms−1,3ms−1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
2ms−1,5ms−1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
3ms−1,7ms−1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is A1ms−1,7ms−1 x=2t2−5t+6⇒v=dxdt=4t−5⇒v=7ms−1att=3seconds.Now,Positionint=3seconds⇒x=18−15+6=9meters.andpositionatt=0secondsis6m⇒Averagevelocity=9−63=1ms−1