Question

A particle moves along a circle of radius $\frac{20}{\pi }m$ with constant tangential acceleration. If the velocity of the particle is $80m/s$ at the end of the second revolution after motion has begin, the tangential acceleration is

• A. $40\pi m/s^2$
• B. $160\pi m/s^2$
• C. $240\pi m/s^2$
• D. $640m/s^2$

Answer 1

The correct option is A $40\pi m/s^2$

Total distance traveled in a revolution $=2\times 2\pi r=2\times 2\times \pi \times \frac{20}{\pi }=80m$

$\therefore v^2-u^2=2as$

$u=0$

$a=\frac{v^2}{2s}$

$a=\frac{{80}^2}{2\times 80}$

$a=40m/s^2$