Question

A particle moves along a circle of radius $\left(\frac{20}{\pi }\right)$m with constant tangential acceleration. If the velocity of the particle is $80m/s$ at the end of the second revolution after motion has begun, the tangential acceleration will be :

• A. $40\pi m/s^2$
• B. $40m/s^2$
• C. $160\pi m/s^2$
• D. $640\pi m/s^2$

Answer 1

The correct option is B $40m/s^2$

We have, $v^2=u^2+2as$
$\Rightarrow (80{)}^2=0+2(a)\left(4\pi \times \frac{20}{\pi }\right)$
[as two revolutions are completed]
$\Rightarrow a=40m/s^2$.