Question

A particle moves along a semicircle of radius $10\text{m}$ in 5 seconds. The magnitude of average velocity of the particle is

• A. $2\pi m{s}^{-1}$
• B. $4\pi m{s}^{-1}$
• C. $2m{s}^{-1}$
• D. $4m{s}^{-1}$

Answer 1

The correct option is D $4m{s}^{-1}$

Average velocity of particle = $\frac{\text{Total displacement}}{\text{Total time}}$
As the particle is moving along a semicircle, so
Displacement of particle = Diameter of the circle
$\Rightarrow$ Average velocity of particle = $\frac{\text{Diameter of circle}}{5}=\frac{2\times 10}{5}=4\text{m/s}$